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Chemical Equations Balanced on 08/18/19

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Cr2O7{2-} + S + H{+} = Cr2O3 + SO2 + OH{-} =>
2 Cr2O7{2-} + 3 S + 2 H{+} = 2 Cr2O3 + 3 SO2 + 2 OH{-}

Be(OH)2 + PbI2 = Pb(OH)2 + BeI2 =>
Be(OH)2 + PbI2 = Pb(OH)2 + BeI2

SODIUM + IODINE = SODIUMIODINE =>
SODIUM + IODINE = SODIUMIODINE

C6H6 + O2 = H2O + CO2 =>
2 C6H6 + 15 O2 = 6 H2O + 12 CO2

Be(OH)2 + CuF = Cu(OH)2 + BeF =>
Be(OH)2 + CuF = Cu(OH)2 + BeF

Fe(NO3)3 + NH3 + H2O = Fe(OH)3 + NH4NO3 =>
Fe(NO3)3 + 3 NH3 + 3 H2O = Fe(OH)3 + 3 NH4NO3

NaI + Pb(SO4)2 = PbI4 + Na2SO4 =>
4 NaI + Pb(SO4)2 = PbI4 + 2 Na2SO4

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

HNO3 + Mg(OH)2 = H2O + Mg(NO3)2 =>
2 HNO3 + Mg(OH)2 = 2 H2O + Mg(NO3)2

RbOH + H3PO4 = Rb3PO4 + H2O =>
3 RbOH + H3PO4 = Rb3PO4 + 3 H2O

Fe + O2 + H2 = Fe(OH)3 =>
2 Fe + 3 O2 + 3 H2 = 2 Fe(OH)3

CaO + MnI4 = MnO2 + CaI2 =>
2 CaO + MnI4 = MnO2 + 2 CaI2

N2H4*H2SO4 + KOH + CHONO(CH3)2 = KN3 + H2O + K2SO4 + CHOH(CH3)2 =>
N2H4*H2SO4 + 3 KOH + CHONO(CH3)2 = KN3 + 4 H2O + K2SO4 + CHOH(CH3)2

S + CI = SCI =>
S + CI = SCI

KHC8H4O4 + NaOH = KNaC8H4O4 + H2O =>
KHC8H4O4 + NaOH = KNaC8H4O4 + H2O

C7H14 + O2 = CO2 + H2O =>
2 C7H14 + 21 O2 = 14 CO2 + 14 H2O

Cu + HNO3 = Cu(NO3)2 + NO + H2O =>
3 Cu + 8 HNO3 = 3 Cu(NO3)2 + 2 NO + 4 H2O

Cu + AgNO3 = Cu(NO3)2 + Ag =>
Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag

(CH3COO)2Zn + Ba(OH)2 = Ba(CH3COO)2 + Zn(OH)2 =>
(CH3COO)2Zn + Ba(OH)2 = Ba(CH3COO)2 + Zn(OH)2

SO2 + O2 = SO3 =>
2 SO2 + O2 = 2 SO3

Pb(NO3)2 + Ba(OH)2 = Ba(NO3)2 + Pb(OH)2 =>
Pb(NO3)2 + Ba(OH)2 = Ba(NO3)2 + Pb(OH)2

KI + NaClO3 + H2SO4 = I2 + K2SO4 + NaCl + H2O =>
6 KI + NaClO3 + 3 H2SO4 = 3 I2 + 3 K2SO4 + NaCl + 3 H2O

Fe2O3 + Cl2 + KOH = K2FeO4 + KCl + H20 =>
4 Fe2O3 + 2 Cl2 + 20 KOH = 8 K2FeO4 + 4 KCl + H20

Fe2O3 + Cl2 + KOH = K2FeO4 + KCl + H2O =>
Fe2O3 + 3 Cl2 + 10 KOH = 2 K2FeO4 + 6 KCl + 5 H2O

Fe + H2O = Fe2O3 + H2 =>
2 Fe + 3 H2O = Fe2O3 + 3 H2

AGNO3 + NAOH = AGOH + NANO3 =>
AGNO3 + NAOH = AGOH + NANO3

Zn + HNO3 = Zn(NO3)2 + NH4NO3 + H2O =>
4 Zn + 10 HNO3 = 4 Zn(NO3)2 + NH4NO3 + 3 H2O

P4 + Br2 = PBr =>
P4 + 2 Br2 = 4 PBr

C9H8O4 + NaHCO3(aq) = CO2(g) + H2O(l) + C9H7NaO4(aq) =>
C9H8O4 + NaHCO3(aq) = CO2(g) + H2O(l) + C9H7NaO4(aq)

CH3Cl + Na + C3H7Cl = C4H10 + NaCl2 =>
CH3Cl + Na + C3H7Cl = C4H10 + NaCl2

KC8H5O4 + O2 = CO2 + KOH + H2O =>
2 KC8H5O4 + 15 O2 = 16 CO2 + 2 KOH + 4 H2O

Al2(SO4)3 = Al2O3 + SO3 =>
Al2(SO4)3 = Al2O3 + 3 SO3

Cr(OH)3 + IO3{-} + OH{-} = CrO4{2-} + I{-} + H2O =>
2 Cr(OH)3 + IO3{-} + 4 OH{-} = 2 CrO4{2-} + I{-} + 5 H2O

Cr(OH)3 + IO3{-} + OH{-} = CrO4{2-} + I{-} + H2O =>
2 Cr(OH)3 + IO3{-} + 4 OH{-} = 2 CrO4{2-} + I{-} + 5 H2O

Cr(OH)3 + IO3{-} + OH{-} = CrO4{2-} + I{-} + H2O =>
2 Cr(OH)3 + IO3{-} + 4 OH{-} = 2 CrO4{2-} + I{-} + 5 H2O

Cr(OH)3 + IO3{-} + OH{-} = CrO4{2-} + I{-} + H2O =>
2 Cr(OH)3 + IO3{-} + 4 OH{-} = 2 CrO4{2-} + I{-} + 5 H2O

NaOH + BaBr = NaBr + BaOH =>
NaOH + BaBr = NaBr + BaOH

Cr(OH)3 + IO3{-} + OH{-} = CrO4{2-} + I{-} + H2O =>
2 Cr(OH)3 + IO3{-} + 4 OH{-} = 2 CrO4{2-} + I{-} + 5 H2O

Mg + HCl = MgCl2 + H2 =>
Mg + 2 HCl = MgCl2 + H2

Ch3COOH + Ba(OH)2 = (Ch3COO)2Ba + H2O =>
2 Ch3COOH + Ba(OH)2 = (Ch3COO)2Ba + 2 H2O

CH3COOH + Ba(OH)2 = (CH3COO)2Ba + H2O =>
2 CH3COOH + Ba(OH)2 = (CH3COO)2Ba + 2 H2O

CaCO3 + C = CaC2 + CO2 =>
2 CaCO3 + 5 C = 2 CaC2 + 3 CO2

K2Cr2O7 + H2SO4 + KI = Cr2(SO4)3 + K2SO4 + H2O + I2 =>
K2Cr2O7 + 7 H2SO4 + 6 KI = Cr2(SO4)3 + 4 K2SO4 + 7 H2O + 3 I2

NaCl + PbBr2 = NaBr + PbCl2 =>
2 NaCl + PbBr2 = 2 NaBr + PbCl2

HgO = Hg + O2 =>
2 HgO = 2 Hg + O2

HgO = Hg + O2 =>
2 HgO = 2 Hg + O2

H2SO4 + Al = Al2(SO4)3 + H2 =>
3 H2SO4 + 2 Al = Al2(SO4)3 + 3 H2

Fe + O2 = Fe2O3 =>
4 Fe + 3 O2 = 2 Fe2O3

H2SO4 + NaHCO3 = Na2SO4 + CO2 + H2O =>
H2SO4 + 2 NaHCO3 = Na2SO4 + 2 CO2 + 2 H2O

S2Cl2 + H2O = SO2 + HCl + S =>
2 S2Cl2 + 2 H2O = SO2 + 4 HCl + 3 S

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Balance equation of any chemical reaction online for free
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