Equations balanced on the previous day | Equations balanced on the next day |
CCl4 + 2 H2O = CO2 + 4 HCl
Ca + ClO3 = Ca(ClO3)2 =>
Ca + 2 ClO3 = Ca(ClO3)2
FeCl2*6H2O + NH4OH = Fe(OH)2 + NH4Cl + H2O =>
FeCl2*6H2O + 2 NH4OH = Fe(OH)2 + 2 NH4Cl + 6 H2O
FeC2O4*2H2O + H2O2 + K2C2O4*H2O + H2C2O4*2H2O = K3[Fe(C2O4)3]*3H2O + H2O =>
2 FeC2O4*2H2O + H2O2 + 3 K2C2O4*H2O + H2C2O4*2H2O = 2 K3[Fe(C2O4)3]*3H2O + 5 H2O
Ca(s) + HOH(l) = H2(g) + Ca(OH)2(aq) =>
Ca(s) + 2 HOH(l) = H2(g) + Ca(OH)2(aq)
FeS + O2 + H2O = Fe2O3 + H2SO4 =>
4 FeS + 9 O2 + 4 H2O = 2 Fe2O3 + 4 H2SO4
C6H10 + O2 = CO2 + H2O =>
2 C6H10 + 17 O2 = 12 CO2 + 10 H2O
CuO + H2SO4 = CuSO4 + H2O =>
CuO + H2SO4 = CuSO4 + H2O
As + NaOCl + H2O = H3AsO4 + NaCl =>
2 As + 5 NaOCl + 3 H2O = 2 H3AsO4 + 5 NaCl
(NH4)2CO3 + NaOH = Na2CO3 + H2O + NH3 =>
(NH4)2CO3 + 2 NaOH = Na2CO3 + 2 H2O + 2 NH3
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
Cr + SnCl2 = Sn + CrCl2 =>
Cr + SnCl2 = Sn + CrCl2
Zn(OH)2 + NH4OH = (NH4)2[Zn(OH)4] =>
Zn(OH)2 + 2 NH4OH = (NH4)2[Zn(OH)4]
Mg3N2 + H2O = H2MgO2 + NH3 =>
Mg3N2 + 6 H2O = 3 H2MgO2 + 2 NH3
NH4H2PO4 + ZnO + Na2CO3 = NaZn(PO3)3 + H2O + NH3 + CO2 =>
6 NH4H2PO4 + 2 ZnO + Na2CO3 = 2 NaZn(PO3)3 + 9 H2O + 6 NH3 + CO2
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
FeC2O4*2H2O + H2O2 + K2C2O4*H2O + H2C2O4*2H2O = K3Fe(C2O4)3*3H2O + H2O =>
2 FeC2O4*2H2O + H2O2 + 3 K2C2O4*H2O + H2C2O4*2H2O = 2 K3Fe(C2O4)3*3H2O + 5 H2O
AgNO3 + NaVO3 + NaOH = Ag3VO4 + NaNO3 + H2O =>
3 AgNO3 + NaVO3 + 2 NaOH = Ag3VO4 + 3 NaNO3 + H2O
H3PO4 + H2S + KCrO7 = K3PO4 + CrPO4 + S8 + H2O =>
32 H3PO4 + 120 H2S + 24 KCrO7 = 8 K3PO4 + 24 CrPO4 + 15 S8 + 168 H2O
C735H1480 + O2 = CO2 + H2O =>
C735H1480 + 1105 O2 = 735 CO2 + 740 H2O
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
Ag[NH3]2{+} + OH{-} = Ag3N + NH3 + H2O =>
3 Ag[NH3]2{+} + 3 OH{-} = Ag3N + 5 NH3 + 3 H2O
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
Al(OH)3 + HCl = Al(OH)2Cl + H2O =>
Al(OH)3 + HCl = Al(OH)2Cl + H2O
(NH4)2CO3MgSO4 = (NH4)2SO4 + MgCO3 =>
(NH4)2CO3MgSO4 = (NH4)2SO4 + MgCO3
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
(NH4)2Fe(SO4)2(aq) + K2[HgI4] + KOH = K2SO4 + Fe[HgI4] + NH3 + H2O =>
(NH4)2Fe(SO4)2(aq) + K2[HgI4] + 2 KOH = 2 K2SO4 + Fe[HgI4] + 2 NH3 + 2 H2O
Cu2 = Cu7 =>
7 Cu2 = 2 Cu7
C2H4OH + O2 = CO2 + H2O =>
4 C2H4OH + 11 O2 = 8 CO2 + 10 H2O
Zn + HIO2 = Zn(IO2)2 + H2 =>
Zn + 2 HIO2 = Zn(IO2)2 + H2
B2S3 + NaOH = B(OH)3 + Na2S =>
B2S3 + 6 NaOH = 2 B(OH)3 + 3 Na2S
KMnO4 + H2C2O4 + HCl = KCl + CO2 + MnCl + H2O =>
KMnO4 + 3 H2C2O4 + 2 HCl = KCl + 6 CO2 + MnCl + 4 H2O
NH3 + Mn = MnNH3 =>
NH3 + Mn = MnNH3
Cu + CO = CuOC =>
Cu + CO = CuOC
(NH4)2SO4 + Ba(NO3)2 = NH4NO3 + Ba2(SO4)2 =>
2(NH4)2SO4 + 2 Ba(NO3)2 = 4 NH4NO3 + Ba2(SO4)2
NiO3 + Mn(OH)2 = Mn2O3 + Ni(OH)2 + H2O =>
NiO3 + 4 Mn(OH)2 = 2 Mn2O3 + Ni(OH)2 + 3 H2O
OS = S + SO3 =>
3 OS = 2 S + SO3
TiO2(s) + H2O(l) = TiOH(s) + HO(g) =>
TiO2(s) + 2 H2O(l) = TiOH(s) + 3 HO(g)
MgO + NH4F = MgF2 + H2O + NH3 =>
MgO + 2 NH4F = MgF2 + H2O + 2 NH3
C3H6O = C6H10O + H2O =>
2 C3H6O = C6H10O + H2O
Al(CO3) = AlO + CO2 =>
Al(CO3) = AlO + CO2
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
Na2O + SO3 = ONa + S =>
3 Na2O + SO3 = 6 ONa + S
C6H14 + C2H4 = C12H26 =>
C6H14 + 3 C2H4 = C12H26
C6H10 + O2 = CO2 + H2O =>
2 C6H10 + 17 O2 = 12 CO2 + 10 H2O
K3[Fe(CN)6] + NaOH = NaCN + KCN + Fe(OH)3 =>
K3[Fe(CN)6] + 3 NaOH = 3 NaCN + 3 KCN + Fe(OH)3
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + K2(NO3)2 =>
2 Cu(NO3)2 + K4[Fe(CN)6] = Cu2[Fe(CN)6] + 2 K2(NO3)2
Cu(OH)2 + H3PO4 = Cu3(PO4)2 + (OH)H =>
3 Cu(OH)2 + 2 H3PO4 = Cu3(PO4)2 + 6(OH)H
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Equations balanced on 11/24/23
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