Equations balanced on the previous day | Equations balanced on the next day |
NH4OH + K2(HgI4) = 2 K + OH + NH4(HgI4)
NaK + H2O = NaK(OH)2 + H2 =>
NaK + 2 H2O = NaK(OH)2 + H2
CuCl2(aq) + Ni(s) = Cu(s) + NiCl3(aq) =>
3 CuCl2(aq) + 2 Ni(s) = 3 Cu(s) + 2 NiCl3(aq)
C*H3*C*H2*C*H3 + O2 = C8CO2 + H2*O =>
3 C*H3*C*H2*C*H3 + 7 O2 = C8CO2 + 12 H2*O
NaOH(s) + CH3COO(aq) = NaCOO + CH3OH =>
NaOH(s) + CH3COO(aq) = NaCOO + CH3OH
H3C2H2OH + KMnO4 + H2SO4 = CH3CO2H + MnSO4 + K2SO4 + H2O =>
5 H3C2H2OH + 4 KMnO4 + 6 H2SO4 = 5 CH3CO2H + 4 MnSO4 + 2 K2SO4 + 11 H2O
KHC2O4 + H2SO4 + KMnO4 = MnSO4 + CO2 + H2O + K2SO4 =>
10 KHC2O4 + 11 H2SO4 + 4 KMnO4 = 4 MnSO4 + 20 CO2 + 16 H2O + 7 K2SO4
CO3(aq) + HNO3(aq) = NO3(s) + CO2(g) + H2O(l) =>
CO3(aq) + 2 HNO3(aq) = 2 NO3(s) + CO2(g) + H2O(l)
FeBr3 + CuSO4 = FeBr3CuSO4 =>
FeBr3 + CuSO4 = FeBr3CuSO4
Ca(OH)2 + CO2 = H2CO3 + Ca + O2 =>
2 Ca(OH)2 + 2 CO2 = 2 H2CO3 + 2 Ca + O2
(C2H5OH) + O2 = CO2 + H2O =>
(C2H5OH) + 3 O2 = 2 CO2 + 3 H2O
Fe3O4 + SO2 = FeS + O2 =>
Fe3O4 + 3 SO2 = 3 FeS + 5 O2
KOH + Al(OH)3{+} = K3(Al(OH)6){+} =>
3 KOH + Al(OH)3{+} = K3(Al(OH)6){+}
KMnO4 + CH3OH = H2O + HCOOH + K + MnO2 =>
KMnO4 + CH3OH = H2O + HCOOH + K + MnO2
Cr2SO43 + NH42CO3 = Cr2CO3 + NH42SO43 =>
Cr2SO43 + NH42CO3 = Cr2CO3 + NH42SO43
K2Cr2O7 + Hg + HCl = KCl + HgCl + Cr2O3 + H2O =>
K2Cr2O7 + 6 Hg + 8 HCl = 2 KCl + 6 HgCl + Cr2O3 + 4 H2O
IBr(aq) + NH3(g) = NI3(s) + NH4Br(aq) =>
3 IBr(aq) + 4 NH3(g) = NI3(s) + 3 NH4Br(aq)
CO2CH4 + O2 = CO2 + H2O =>
CO2CH4 + 2 O2 = 2 CO2 + 2 H2O
Li3PO = Li + P + O =>
Li3PO = 3 Li + P + O
BaCl + HNO3 = BaNO3 + HCl =>
BaCl + HNO3 = BaNO3 + HCl
N + Cl = N2Cl =>
2 N + Cl = N2Cl
C8H10 = C + H =>
C8H10 = 8 C + 10 H
K2Cr2O7 + HCl + H{+} = Cl2 + Cr{3+} + H2O + K =>
K2Cr2O7 + 8 HCl + 6 H{+} = 4 Cl2 + 2 Cr{3+} + 7 H2O + 2 K
C2H7N + O2 = CO2 + H2O + NO2 =>
4 C2H7N + 19 O2 = 8 CO2 + 14 H2O + 4 NO2
XAgNO3 + XCr(C2H3O2)3 = XAgC2H3O2 + XCr(NO3)3 =>
3 XAgNO3 + XCr(C2H3O2)3 = 3 XAgC2H3O2 + XCr(NO3)3
CO + CO2 = COC2O3 =>
2 CO + CO2 = COC2O3
HF(aq) + NaOH(aq) = H2O(l) + NaF(aq) =>
HF(aq) + NaOH(aq) = H2O(l) + NaF(aq)
CaSO4 + K2S = CaS + K2SO4 =>
CaSO4 + K2S = CaS + K2SO4
NH4OH + H2SO4 = N2H8SO4 + H2O =>
2 NH4OH + H2SO4 = N2H8SO4 + 2 H2O
H2PO3H + NaOH = Na2PO3H + H2O =>
H2PO3H + 2 NaOH = Na2PO3H + 2 H2O
FeCl3 + NaNo3 = NaCl + Fe(No3)3 =>
FeCl3 + 3 NaNo3 = 3 NaCl + Fe(No3)3
Al(OH)3 + HSO4 = Al + SO4 + H2O =>
Al(OH)3 + 3 HSO4 = Al + 3 SO4 + 3 H2O
Cu(NO3)2H2O(s) = CuO(s) + NO2(g) + O2(g) + H2O(g) =>
2 Cu(NO3)2H2O(s) = 2 CuO(s) + 4 NO2(g) + O2(g) + 2 H2O(g)
Mg + Zn(PO4)2 = Zn + Mg(PO4) =>
2 Mg + Zn(PO4)2 = Zn + 2 Mg(PO4)
H2TeO4 + Hg(OH)2 = HgTeO4 + H2O =>
H2TeO4 + Hg(OH)2 = HgTeO4 + 2 H2O
K2CO3 + HNO3 = K2(NO3)2 + CO2 + H2O =>
K2CO3 + 2 HNO3 = K2(NO3)2 + CO2 + H2O
H2 + (PO4) = H3(PO4) =>
3 H2 + 2(PO4) = 2 H3(PO4)
CoCl2 + (NH4)2[Hg(SCN)4] + ZnCl2 = Co[Hg(SCN)4]*Zn[Hg(SCN)4] + NH4Cl =>
CoCl2 + 2(NH4)2[Hg(SCN)4] + ZnCl2 = Co[Hg(SCN)4]*Zn[Hg(SCN)4] + 4 NH4Cl
Na3PO4 + K = KPO4 + Na =>
Na3PO4 + K = KPO4 + 3 Na
Pb(NO3)2 + CaCl2 = PbCl2Ca(NO3)2 =>
Pb(NO3)2 + CaCl2 = PbCl2Ca(NO3)2
Fe3O4(s) + CO(g) = Fe(s) + CO2(g) =>
Fe3O4(s) + 4 CO(g) = 3 Fe(s) + 4 CO2(g)
FeO3(s) + CO = Fe(s) + CO2 =>
FeO3(s) + 3 CO = Fe(s) + 3 CO2
PB(CH3COO)2 + KI = PBI2 + CH3COOK =>
PB(CH3COO)2 + 2 KI = PBI2 + 2 CH3COOK
CrCl3 + Br2 + KOH = KCl + KBr + K2CrO4 + H2O =>
2 CrCl3 + 3 Br2 + 16 KOH = 6 KCl + 6 KBr + 2 K2CrO4 + 8 H2O
HCl(aq) + Ni(NO3)2(aq) = HNO3 + NiCl2 =>
2 HCl(aq) + Ni(NO3)2(aq) = 2 HNO3 + NiCl2
PbO + Br = PbBr2 + O =>
PbO + 2 Br = PbBr2 + O
NH + (NO3)4 = N2 + H2O =>
24 NH + (NO3)4 = 14 N2 + 12 H2O
K3N + BaSO4 = K3Ba + NSO4 =>
K3N + BaSO4 = K3Ba + NSO4
ZnSO4*7H2O(aq) + Na2SO4(aq) = ZnSO4(aq) + Na2SO4*10H2O(aq) =>
10 ZnSO4*7H2O(aq) + 7 Na2SO4(aq) = 10 ZnSO4(aq) + 7 Na2SO4*10H2O(aq)
Fe(s) + Pb(NO3)2(aq) = Pb(s) + FeNO3(aq) =>
2 Fe(s) + Pb(NO3)2(aq) = Pb(s) + 2 FeNO3(aq)
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/01/23
Equations balanced on 12/31/22
Deixe seu comentário sobre a sua experiência com o balanceador de equação química.