Equations balanced on the previous day | Equations balanced on the next day |
2 C6H6 + 15 O2 = 12 CO2 + 6 H2O
C3H7COOH(l) + O2(g) = CO2(g) + H2O(g) =>
C3H7COOH(l) + 5 O2(g) = 4 CO2(g) + 4 H2O(g)
Na2SO3 + Cl2 + H2O = Na2SO4 + HCl =>
Na2SO3 + Cl2 + H2O = Na2SO4 + 2 HCl
AgNO3(aq) + HCl = AgCl + HNO3 =>
AgNO3(aq) + HCl = AgCl + HNO3
Na2FeO4 + H2O2 = Fe(OH)3 + NaOH + O2 =>
2 Na2FeO4 + 5 H2O2 = 2 Fe(OH)3 + 4 NaOH + 4 O2
Fe + Pb(NO3)2 = Pb2 + FeNO3 =>
4 Fe + 2 Pb(NO3)2 = Pb2 + 4 FeNO3
(CuOH)2SO4 + NH4OH + (NH4)2SO4 = [Cu(NH3)4]SO4 + H2O =>
(CuOH)2SO4 + 6 NH4OH + (NH4)2SO4 = 2[Cu(NH3)4]SO4 + 8 H2O
Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3
AlKNO2 = Al + KNO2 =>
AlKNO2 = Al + KNO2
C8H18 + O2 = C8 + H2O =>
2 C8H18 + 9 O2 = 2 C8 + 18 H2O
HCI + (NH4)2S = NH4CI + H2S =>
2 HCI + (NH4)2S = 2 NH4CI + H2S
HNO3 + Pd(OH)2 = Pd(NO3)2 + H2O =>
2 HNO3 + Pd(OH)2 = Pd(NO3)2 + 2 H2O
Cu + H2SO4*H2O = CuSO4 + SO2 + H2O =>
Cu + 2 H2SO4*H2O = CuSO4 + SO2 + 4 H2O
Na2CO3(H2O)10 + HCl = CO2 + H2O + NaCl =>
Na2CO3(H2O)10 + 2 HCl = CO2 + 11 H2O + 2 NaCl
Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3
CO2 + H2O = C6H12O6 + O2 =>
6 CO2 + 6 H2O = C6H12O6 + 6 O2
Cu(OH)2 + K3[Fe(CN)6] = Cu3Fe(CN)6 + K(OH)2 =>
3 Cu(OH)2 + K3[Fe(CN)6] = Cu3Fe(CN)6 + 3 K(OH)2
BaCl2 + H2SO4 = BaSO4 + HCl =>
BaCl2 + H2SO4 = BaSO4 + 2 HCl
Sr(NO3)2(aq) + Na2S(aq) = SrS(aq) + NaNO3 =>
Sr(NO3)2(aq) + Na2S(aq) = SrS(aq) + 2 NaNO3
KClO3 + C27H57 = CO2 + KCl + H2O =>
55 KClO3 + 2 C27H57 = 54 CO2 + 55 KCl + 57 H2O
Na2S + KMnO4 + NaOH = S + Na2MnO4 + KOH =>
Na2S + 2 KMnO4 + 2 NaOH = S + 2 Na2MnO4 + 2 KOH
C3H7COOH(l) + O2(g) = CO2(g) + H2O(g) =>
C3H7COOH(l) + 5 O2(g) = 4 CO2(g) + 4 H2O(g)
Cu(OH)2 + K3[Fe(CN)6] = Cu3Fe(CN)6 + K(OH)2 =>
3 Cu(OH)2 + K3[Fe(CN)6] = Cu3Fe(CN)6 + 3 K(OH)2
Cr(CO)6 + HNO3 = CO2 + NO + H2CrO4 + H2O =>
Cr(CO)6 + 6 HNO3 = 6 CO2 + 6 NO + H2CrO4 + 2 H2O
PbCH3 + KMnO4 + H2SO4 = H2O + K2SO4 + MnSO4 + PbCOOH =>
5 PbCH3 + 6 KMnO4 + 9 H2SO4 = 14 H2O + 3 K2SO4 + 6 MnSO4 + 5 PbCOOH
Nd2(C2O4)3 + H2SO4 = Nd2(SO4)3 + H2O + CO2 + SO =>
2 Nd2(C2O4)3 + 9 H2SO4 = 2 Nd2(SO4)3 + 9 H2O + 12 CO2 + 3 SO
HCl + Ba(OH)2 = BaCl2 + H2O =>
2 HCl + Ba(OH)2 = BaCl2 + 2 H2O
NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O
Fe(OH)3 + (NH4)2CO3 = NH4OH + Fe2(CO3)3 =>
2 Fe(OH)3 + 3(NH4)2CO3 = 6 NH4OH + Fe2(CO3)3
NaOH + CH3CH(Cl)CH2CH3 = NaCl + CH3CH(OH)CH2CH3 =>
NaOH + CH3CH(Cl)CH2CH3 = NaCl + CH3CH(OH)CH2CH3
MnCl + (NH4)2 + CO3 = MnCO3 + NH4Cl =>
2 MnCl + (NH4)2 + 2 CO3 = 2 MnCO3 + 2 NH4Cl
HCl + Ca(OH)2 = CaCl2 + H2O =>
2 HCl + Ca(OH)2 = CaCl2 + 2 H2O
C8H9O2N + O = CO2 + H2O + N =>
2 C8H9O2N + 37 O = 16 CO2 + 9 H2O + 2 N
Cu(OH)2 + K3[Fe(CN)6] = Cu3Fe(CN)6 + K(OH)2 =>
3 Cu(OH)2 + K3[Fe(CN)6] = Cu3Fe(CN)6 + 3 K(OH)2
C2H5O + O2 = H2O + C2H2 =>
4 C2H5O + O2 = 6 H2O + 4 C2H2
H2CO3 = H2O + CO2 =>
H2CO3 = H2O + CO2
Ta7B4C4 + Ta3B4 + C = Ta7B8C2 =>
Ta7B4C4 + 7 Ta3B4 + 4 C = 4 Ta7B8C2
NaOH + CH3CH(Cl)CH2CH3 = NaCl + CH3CH(OH)CH2CH3 =>
NaOH + CH3CH(Cl)CH2CH3 = NaCl + CH3CH(OH)CH2CH3
H2O2 + NaBr = Na2OH + Br2 =>
H2O2 + 4 NaBr = 2 Na2OH + 2 Br2
Cu(OH)2 + K3[Fe(CN)6] = Cu3Fe(CN)6 + K(OH)2 =>
3 Cu(OH)2 + K3[Fe(CN)6] = Cu3Fe(CN)6 + 3 K(OH)2
C2H5O + O2 = H2O + C2H2 =>
4 C2H5O + O2 = 6 H2O + 4 C2H2
C21H44 + O2 = CO + H2O =>
2 C21H44 + 43 O2 = 42 CO + 44 H2O
ClO2 + H2O + H3AsO3 = H3AsO4 + HCl =>
2 ClO2 + H2O + 5 H3AsO3 = 5 H3AsO4 + 2 HCl
H2O2 + NaBr = Na2OH + Br2 =>
H2O2 + 4 NaBr = 2 Na2OH + 2 Br2
Ta7B4C4 + Ta3B4 + C = Ta7B8C2 =>
Ta7B4C4 + 7 Ta3B4 + 4 C = 4 Ta7B8C2
MnCl2 + O = Mn3O4 + ClO =>
3 MnCl2 + 10 O = Mn3O4 + 6 ClO
NH4 + NO3(s) = N2O(g) + H2O(l) =>
NH4 + NO3(s) = N2O(g) + 2 H2O(l)
H2O2 + NaBr = Na2OH + Br2 =>
H2O2 + 4 NaBr = 2 Na2OH + 2 Br2
KMnO4 + Br + H = KBr + HMnO4 =>
KMnO4 + Br + H = KBr + HMnO4
Fe(s) + CuNo3(aq) = Cu(s) + Fe(No3)2(aq) =>
Fe(s) + 2 CuNo3(aq) = 2 Cu(s) + Fe(No3)2(aq)
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/19/24
Equations balanced on 03/20/23
Deixe seu comentário sobre a sua experiência com o balanceador de equação química.