Primeiro, calcule o número de cada átomo em He1250H5302Li900Be600Ne424S832C901Pa100Np123U232Bk12OW123Au3:
He: 1250, H: 5302, Li: 900, Be: 600, Ne: 424, S: 832, C: 901, Pa: 100, Np: 123, U: 232, Bk: 12, O: 1, W: 123, Au: 3
Em seguida, pesquise os pesos atômicos para cada elemento da tabela periódica :
He: 4.002602, H: 1.00794, Li: 6.941, Be: 9.012182, Ne: 20.1797, S: 32.065, C: 12.0107, Pa: 231.03588, Np: 236.04657, U: 238.02891, Bk: 247.070307, O: 15.9994, W: 183.84, Au: 196.966569
Agora, calcule a soma dos produtos do número de átomos pelo peso atômico:
Massa molar (He1250H5302Li900Be600Ne424S832C901Pa100Np123U232Bk12OW123Au3) = ∑ Counti * Weighti =
Count(He) * Weight(He) + Count(H) * Weight(H) + Count(Li) * Weight(Li) + Count(Be) * Weight(Be) + Count(Ne) * Weight(Ne) + Count(S) * Weight(S) + Count(C) * Weight(C) + Count(Pa) * Weight(Pa) + Count(Np) * Weight(Np) + Count(U) * Weight(U) + Count(Bk) * Weight(Bk) + Count(O) * Weight(O) + Count(W) * Weight(W) + Count(Au) * Weight(Au) =
1250 * 4.002602 + 5302 * 1.00794 + 900 * 6.941 + 600 * 9.012182 + 424 * 20.1797 + 832 * 32.065 + 901 * 12.0107 + 100 * 231.03588 + 123 * 236.04657 + 232 * 238.02891 + 12 * 247.070307 + 1 * 15.9994 + 123 * 183.84 + 3 * 196.966569 =
201601.5591 g/mol
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